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X^2+25X-175=0
a = 1; b = 25; c = -175;
Δ = b2-4ac
Δ = 252-4·1·(-175)
Δ = 1325
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1325}=\sqrt{25*53}=\sqrt{25}*\sqrt{53}=5\sqrt{53}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{53}}{2*1}=\frac{-25-5\sqrt{53}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{53}}{2*1}=\frac{-25+5\sqrt{53}}{2} $
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